r(t)=h_s(t)·s(t)+h_j(t)·J(t)+n(t)

P_r=P_j+G_j+G_r-L

P_r= \frac{G_j{A}_r{P}_j}{4\pi d^2}

L=10lg \frac{4\pi d^2}{G_j{A}_r}

\frac{G_j}{A_r}= \frac{4\pi }{{\lambda }^2}

L=10lg \frac{{\left(4\pi d\right)}^2}{G_j{G}_r{\lambda }^2}

P_r=P_j-32-20lgf-20lgd+G_j+G_r

P_rs+10lg(J/S)≤P_rj

P_j≥P \frac{G_s}{G_j} \frac{d_j^2}{d_s^2} \frac{J}{S}

d₁= \sqrt{{\left({\int }_0^{t}v\left(t\right)dt+R_1\right)}^2+h_1^2}

d₂= \sqrt{{\left(△d+{\int }_0^{t_{}}v\left(t\right)dt\right)}^2+R_2^2+h_2^2-\Delta d^2}

s_I= \frac{s_x^{2}T}{2}+ \frac{J_x{s}_{x}cos{\phi }_{J_x}T}{2}+ \frac{s_x{\int }_{nT}^{(n+1)T}{n}_c\left(t\right)dt}{2}

P_I \left(x\right)= \frac{1}{\sqrt{2\pi {\delta }_I}}exp \left[-\frac{{\left(x-{\mu }_I\right)}^2}{2{\delta }_I^2}\right]

μ_I=E \left\{s_I\right\}= \frac{s_x^{2}T}{2}+ \frac{J_x{s}_{x}cos{\phi }_{J_x}T}{2}

p_xk=p \left(r\le (k-1)\xi \right)=1-Q \left(\frac{(k-1)\xi -{\mu }_{Ik}}{{\delta }_I}\right)

p_I= \frac{1}{k} \left\{1-Q\left(\frac{(k-1)\xi -{\mu }_{Ik}}{{\delta }_I}\right)+Q\left(\frac{\xi -{\mu }_{I1}}{{\delta }_I}\right)+\right. \left.\sum _{m=2}^{k-1}\left[1+Q\left(\frac{m\xi -{\mu }_{Im}}{{\delta }_I}\right)-Q\left(\frac{\left(m-1\right)\xi -{\mu }_{Ik}}{{\delta }_I}\right)\right]\right\}

p_Q= \frac{1}{k} \left\{1-Q\left(\frac{(k-1)\xi -{\mu }_{Ik}}{{\delta }_Q}\right)+Q\left(\frac{\xi -{\mu }_{Q1}}{{\delta }_Q}\right)+\right. \left.\sum _{m=2}^{k-1}\left[1+Q\left(\frac{m\xi -{\mu }_{Qm}}{{\delta }_Q}\right)-Q\left(\frac{\left(m-1\right)\xi -{\mu }_{Qk}}{{\delta }_Q}\right)\right]\right\}

t_总=t_截获+t_分析+t_干扰+t_传输

t= \frac{\left(L_J-L_t\right)}{\sigma R}

v= \frac{J^2}{A^2}

u= \frac{A^2}{2{\delta }^2}

P= \frac{1}{4}erfc \left(\sqrt{\frac{u}{2}}\left(1-\sqrt{v}\right)\right)+ \frac{1}{4}erfc \left(\sqrt{\frac{u}{2}}\left(1+\sqrt{v}\right)\right)